In all cells with initial values you can put data
All the values are calculated by the classical formula for a mean value and
the breeding value is defined as shown below. To see the results
press the Calculate button.
Compare the results, for which gene frequency are there the smallest
difference in breeding value between the three genotypes and the smallest
additive variance? why ?
The halothane locus (Hal) has influence on the quality of
swine meat on the basis of a meat quality index where meat colour
is the main component. The average index for the (Hal) genotypes
are given below:
Example:
The test example is the transfferin example given in Veterinary Genetics. Jersey
cows with the genotype tt yield 2082 kg milk
and cows with the genotypes Tt and TT yield 1882 kg milk. The
gene frequencies p(T) and q(t) are given as 0,67 and 0,33, respectively.
Questions:
Calculate the breeding value and dominance deviation for the gene frequencies
p equal .1, .2, .3, .4, .5, .6, .7, .8 and .9 for the following genotypic
values
A2A2 100
A1A2 115
A1A1 110
Genotype Meat-quality-index
N/N 8.00
N/n 7.10
n/n 6.00
Suppose that the frequency of q(n) = 0.20 calculate the following:
a) the average Meat-quality-index for the population,
b) the average Meat-quality-index for offspring from
individuals with the genotype
N/N respectively n/n supposing adef mating in the population,
c) the breeding value of the three genotypes
d) the additive variance, due to the halothane locus,
e) the proportion of the additive varianceHal
of the total additive variance for the Meat-quality-index
as its h2 = 0,44 and varianceP =1,69.