In all cells with initial values you can put data
 All the values are calculated by the classical formula for a mean value and
the breeding value is defined as shown below. To see the results 
press the Calculate button.
 Compare the results, for which gene frequency are there the smallest
difference in breeding value between the three genotypes and the smallest 
additive variance? why ?
 The halothane locus (Hal) has influence on the quality of
 swine meat on the basis of a meat quality index where meat colour
is the main component. The average index for the (Hal) genotypes 
are given below:
Example:
The test example is the  transfferin example given in  Veterinary Genetics. Jersey 
cows with the  genotype  tt yield 2082 kg milk
and cows with the  genotypes Tt and TT yield 1882 kg milk. The 
gene frequencies p(T) and q(t) are given as  0,67 and 0,33, respectively.

Questions:
Calculate the breeding value and dominance deviation  for the gene frequencies
 p equal  .1, .2,  .3, .4, .5, .6, .7, .8 and .9 for the following genotypic 
values
A2A2    100
A1A2    115
A1A1    110
			Genotype	Meat-quality-index
			 N/N 	        8.00
			 N/n  	        7.10
			 n/n  	        6.00
Suppose that the frequency of q(n) = 0.20 calculate the following:
	a)	the average Meat-quality-index for the population, 
	b)	the average Meat-quality-index for offspring from 
individuals with the genotype  
		N/N respectively n/n supposing adef mating  in the population,
	c)	the breeding value of the three genotypes
	d)	the additive variance, due to the halothane locus,
e)	the proportion of the  additive varianceHal
 of the  total additive variance for the Meat-quality-index
		as its h2 = 0,44 and varianceP =1,69.